For the reaction below, Kc = 0.534 at 700 degrees Celsius. A mixture of 0.250 moles of CO and 0.450 moles of H20 are heated to 700 degrees Celsius in a 10.0 L container. Calculate the concentrations of all four species when equilibirium is reached.
H2 + CO2 ---%26gt; H20 + CO
I'm pretty sure everything is right im just not sure about a couple of significant digits, so if anyone can help it would be appreacited.
first I got the Molarity of CO - .250 moles/10L = .025M and
H20 .450 moles/10L = .045 M
next I did the ICE method to come up with the problem (.025-x)(.045-x)/x^2=0.534
I work this out to get it equal to 0 and it looks like:
.466x^2-.070x+.0011=0
should it be .001125?
I use the solve function on my calculator, And this gives me x=.0183 so, if everything is correct then the concentrations should be:
CO = .025-.018 = .007
H20 = .045-.018 = .027
H2 =.018
CO2 = .018
How does this look? Just want to know that im doing this right...Im not sure if x should be .018 or .0183 Thanks
Significant fig help?
.0183 because you need 3 significant figures
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