If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor. 3.00

If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor.

3.00 μF capacitor __________ V

4.00 μF capacitor __________V

2.00 μF capacitor __________ V



Fig. 19-52 Link ..

http://img.photobucket.com/albums/v706/E...

If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor. 3.00
Capacitor_________Impedance (?)

3 μF______________1062

4 μF______________796.2

2 μF______________1592.4



i 1 is current thro` 3μF and 4μF capacitors

i 2 is current thro` 2 μF capacitor.



i 1 = (25.6 / 1858.2) x 1000 mA = 13.8 mA

i 2 = (25.6 / 1592.4) x 1000 mA = 16.1 mA
Reply:Thank you for vote Report It
Reply:1/3+1/4+1/2=1/c

c=12/13

c=q/v

find q

for each capacitor v=q/c
Reply:2.00μF = 25.6 V

Because it is connected in parallel



4.00μF and 3.00μF are in series

Charge between is the same which Q .



4.00μF = Q/V1

3.00μF = Q/V2



Combined = (4x3)/(4+3) = 12/7 μF



12/7μF = Q/25.6

Q = 1536/35 μC



4.00μF = (1536/35μC) / V1

V1 = 10.97 V

3.00μF = (1536/35μC)/V2

V2 = 14.63 V