Particles of charge Q1 = +64 µC, Q2 = +53 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center on

Particles of charge Q1 = +64 μC, Q2 = +53 μC, and Q3 = -80 μC are placed in a line (Fig. 16-37). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two.



Image: http://i27.tinypic.com/nvbno8.gif





Force on Q1

Magnitude=___N



Force on Q2

Magnitude=___N



Force on Q3

Magnitude=___N







Please explain your answer. Also, I have several other physics questions open, so if you get a chance, please look those up as well. Thanks!!

Particles of charge Q1 = +64 μC, Q2 = +53 μC, and Q3 = -80 μC are placed in a line (Fig. 16-37). The center on
The magnitude of force from one to the other is

F=C*q1*q2/d^2





Q1

F=-C*q1*(q2/0.35^2+q3/0.70^2)

be careful of signs

F= -155 N





Q2

F= C*q2*(q1/0.35^2-q3/0.35^2)

note the signs

F=560 N







Q3

F= -C*q3*(q1/0.7^2+q2/0.35^2)

note the signs

F=405 N



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